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Fluid Equations in Cartesian Coordinates

Let us adopt the conventional Cartesian coordinate system, $x$, $y$, $z$. According to Equation (26), the various components of the stress tensor are
$\displaystyle \sigma_{xx}$ $\textstyle =$ $\displaystyle -p + 2\,\mu\,\frac{\partial v_x}{\partial x},$ (127)
$\displaystyle \sigma_{yy}$ $\textstyle =$ $\displaystyle -p + 2\,\mu\,\frac{\partial v_y}{\partial y},$ (128)
$\displaystyle \sigma_{zz}$ $\textstyle =$ $\displaystyle -p + 2\,\mu\,\frac{\partial v_z}{\partial z},$ (129)
$\displaystyle \sigma_{xy}=\sigma_{yx}$ $\textstyle =$ $\displaystyle \mu\left(\frac{\partial v_x}{\partial y}+\frac{\partial v_y}{\partial x}\right),$ (130)
$\displaystyle \sigma_{xz}=\sigma_{zx}$ $\textstyle =$ $\displaystyle \mu\left(\frac{\partial v_x}{\partial z}+\frac{\partial v_z}{\partial x}\right),$ (131)
$\displaystyle \sigma_{yz}=\sigma_{zy}$ $\textstyle =$ $\displaystyle \mu\left(\frac{\partial v_y}{\partial z}+\frac{\partial v_z}{\partial y}\right),$ (132)

where ${\bf v}$ is the velocity, $p$ the pressure, and $\mu$ the viscosity. The equations of compressible fluid flow, (87)-(89) (from which the equations of incompressible fluid flow can easily be obtained by setting $\Delta=0$), become
$\displaystyle \frac{D\rho}{Dt}$ $\textstyle =$ $\displaystyle -\rho\,\Delta,$ (133)
$\displaystyle \frac{Dv_x}{Dt}$ $\textstyle =$ $\displaystyle - \frac{1}{\rho}\,\frac{\partial p}{\partial x} - \frac{\partial{...
...rho}\left(\nabla^2 v_x + \frac{1}{3}\,\frac{\partial\Delta}{\partial x}\right),$ (134)
$\displaystyle \frac{Dv_y}{Dt}$ $\textstyle =$ $\displaystyle - \frac{1}{\rho}\,\frac{\partial p}{\partial y} - \frac{\partial{...
...rho}\left(\nabla^2 v_y + \frac{1}{3}\,\frac{\partial\Delta}{\partial y}\right),$ (135)
$\displaystyle \frac{Dv_z}{Dt}$ $\textstyle =$ $\displaystyle - \frac{1}{\rho}\,\frac{\partial p}{\partial z} - \frac{\partial{...
...rho}\left(\nabla^2 v_z + \frac{1}{3}\,\frac{\partial\Delta}{\partial z}\right),$ (136)
$\displaystyle \frac{1}{\gamma-1}\left(\frac{D\rho}{Dt} - \frac{\gamma\,p}{\rho}\,\frac{D\rho}{Dt}\right)$ $\textstyle =$ $\displaystyle \chi + \frac{\kappa\,{\cal M}}{{\cal R}}\,\nabla^2\left(\frac{p}{\rho}\right),$ (137)

where $\rho$ is the mass density, $\gamma$ the ratio of specific heats, $\kappa$ the heat conductivity, ${\cal M}$ the molar mass, and ${\cal R}$ the molar ideal gas constant. Furthermore,
$\displaystyle \Delta$ $\textstyle =$ $\displaystyle \frac{\partial v_x}{\partial x} + \frac{\partial v_y}{\partial y} + \frac{\partial v_z}{\partial z},$ (138)
$\displaystyle \frac{D}{Dt}$ $\textstyle =$ $\displaystyle \frac{\partial}{\partial t} + v_x\,\frac{\partial }{\partial x} + v_y\,\frac{\partial}{\partial y} + v_z\,\frac{\partial}{\partial z},$ (139)
$\displaystyle \nabla^2$ $\textstyle =$ $\displaystyle \frac{\partial^2}{\partial x^2} + \frac{\partial^2}{\partial y^2}+\frac{\partial^2}{\partial z^2},$ (140)
$\displaystyle \chi$ $\textstyle =$ $\displaystyle 2\,\mu\left[\left(\frac{\partial v_x}{\partial x}\right)^2+\left(...
...\frac{\partial v_x}{\partial y}+\frac{\partial v_y}{\partial x}\right)^2\right.$  
    $\displaystyle \left.+\frac{1}{2}\left(\frac{\partial v_x}{\partial z}+\frac{\pa...
...frac{\partial v_y}{\partial z}+\frac{\partial v_z}{\partial y}\right)^2\right].$ (141)

In the above, $\gamma$, $\mu$, $\kappa$, and ${\cal M}$ are treated as uniform constants.


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Next: Fluid Equations in Cylindrical Up: Mathematical Models of Fluid Previous: Dimensionless Numbers in Compressible
Richard Fitzpatrick 2012-04-27