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According to Section 2.10, the solution to the Newmann problem, in which the charge density is specified
within some volume
, and the normal derivative of the potential given on the bounding surface
,
takes the form
 |
(382) |
where the Newmann Green's function is
written
 |
(383) |
Here,
is solution of Laplace's equation (i.e.,
) which is chosen so as to ensure that
 |
(384) |
and
 |
(385) |
The latter constraint holds when
(or
) lies on
. Note that we have chosen the arbitrary constant to which the potential
is undetermined such that
.
It again follows from Sections 3.4 and 3.5
that
where the
and the
are chosen in such a manner that the constraints (385) and (386) are satisfied.
As a specific example, suppose that the volume
lies inside the spherical surface
.
The physical constraint that the Green's function remain finite at
implies that the
are all zero.
Applying the constraint (385) at
, we get
 |
(387) |
Similarly, the constraint (386) leads to
 |
(388) |
for
.
Hence, the unique Green's function for the problem becomes
Finally, expanding
and
in the forms (378) and (379), respectively, Equations (383) and
(390) yield
 |
(390) |
and
for
.
Next: Laplace's Equation in Cylindrical
Up: Potential Theory
Previous: Dirichlet Problem in Spherical
Richard Fitzpatrick
2014-06-27