Sound Waves
A sound wave is a type of longitudinal wave that causes a disturbance in the pressure and density of an ideal gas through which it passes.
Consider a plane sound wave propagating in the
-direction.
Let
be the longitudinal displacement of the gas associated with the wave. Consider a slab of gas of
cross-sectional area
lying between
and
. The mass of the slab is
, where
is gas's mass density. The slab's equation of longitudinal motion is
![$\displaystyle \rho\,A\,dx\,\frac{\partial^{2}\xi}{\partial t^{2}} = A\left[-p(x+dx/2)+p(x-dx/2)\right]=-A\,\frac{\partial p}{\partial x}\,dx,$](img3671.png) |
(5.155) |
which gives
![$\displaystyle \rho\,\frac{\partial^{2}\xi}{\partial t^{2}}=-\frac{\partial p}{\partial x}.$](img3672.png) |
(5.156) |
The change in volume of the slab of gas is
![$\displaystyle \delta V = A\left[\xi(x+dx/2)-\xi(x-dx/2)\right]=A\,\frac{\partial\xi}{\partial x}\,dx,$](img3673.png) |
(5.157) |
which yields
![$\displaystyle \frac{\delta V}{V} =\frac{\partial\xi}{\partial x},$](img3674.png) |
(5.158) |
because
. However,
![$\displaystyle \frac{\delta V}{V} = -\frac{\delta p}{\kappa},$](img3676.png) |
(5.159) |
where
is the bulk modulus. [See Equation (5.146).]
Hence,
![$\displaystyle \frac{\partial \xi}{\partial x} = -\frac{\delta p}{\kappa}.$](img3677.png) |
(5.160) |
Equation (5.156) gives
![$\displaystyle \rho\,\frac{\partial^{2}}{\partial t^{2}}\!\left(\frac{\partial \xi}{\partial x}\right)=-\frac{\partial^{2} \delta p}{\partial x^{2}},$](img3678.png) |
(5.161) |
writing
, where
is a constant background pressure.
The previous two equations can be combined to yield
![$\displaystyle \frac{\partial^{2}\delta p}{\partial t^{\,2}} = v_s^{\,2}\,\frac{\partial^{2} \delta p}{\partial x^{\,2}},$](img3680.png) |
(5.162) |
where
![$\displaystyle v_s= \left(\frac{\kappa}{\rho}\right)^{1/2}.$](img3681.png) |
(5.163) |
Equation (5.162) is a one-dimensional wave equation that has the standard solution
![$\displaystyle \delta p(x, t)=\delta p_0 \,\cos[k\,(x-v_s\,t)],$](img3682.png) |
(5.164) |
where
and
are constants. The previous solution corresponds to a wave-like
disturbance in the gas pressure of amplitude
, wavenumber
, and
phase velocity
. In other words, Equation (5.163) specifies the speed of sound in an ideal gas.
It remains to determine whether the compression of the gas associated with the passage of a sound wave is
isothermal or isentropic. In fact, because ideal gases are relatively poor conductors of heat (see Section 5.3.10), the period of vibration
of a sound wave is generally much shorter than the relaxation time necessary for a small
element of the gas to exchange energy with the remainder of the gas by means of heat
flow. Hence, the compression of the gas associated with the passage of a sound wave is isentropic.
It follows from Equations (5.154) and (5.163) that the speed of sound in an ideal gas is
![$\displaystyle v_s = \left(\frac{\kappa_S}{\rho}\right)^{1/2}=\left(\frac{\gamma\,p}{\rho}\right)^{1/2}.$](img3686.png) |
(5.165) |
Making use of Equations (5.97) and (5.129), the previous equation becomes
![$\displaystyle v_s =\left(\frac{\gamma\,R\,T}{\mu}\right)^{1/2},$](img3687.png) |
(5.166) |
where
is the molecular mass. Note that the speed of sound in an ideal gas only depends on the
gas temperature, and is independent of the pressure.
It is a good approximation to treat the Earth's atmosphere as an ideal gas. The atmosphere is
mostly diatomic, which implies that
. [See Equation (5.122).] Moreover, the
molecular weight of the atmosphere is
kg. (See Section 5.2.6.) Hence,
the speed of sound in air at
C is
.