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Equilibrium of Isolated System

Consider a thermally isolated system, $ A$ . According to Section 5.6, any spontaneously occurring process is such that the system's entropy tends to increase in time. In statistical terms, this means that the system evolves toward a situation of greater intrinsic probability. Thus, in any spontaneous process, the change in entropy satisfies

$\displaystyle {\mit\Delta} S \geq 0.$ (9.1)

It follows that if a stable equilibrium state has been attained [i.e., one in which no further spontaneous processes (other than random fluctuations) can take place] then this state is such that $ S$ is maximized. In other words, it is the most probable state of the system, subject to the given constraints. Thus, we can make the following statement:
For a thermally isolated system, the stable equilibrium state is such that

$\displaystyle S = {\rm maximum}.$    

Now, in a thermally isolated system, the first law of thermodynamics implies that

$\displaystyle 0=Q = W+{\mit\Delta}\overline{E},$ (9.2)

or

$\displaystyle W =\left(-{\mit\Delta}\overline{E}\right).$ (9.3)

If the external parameters of the system (e.g., its volume) are kept fixed, so that no work is done (i.e., $ W=0$ ), then

$\displaystyle \overline{E} = {\rm constant}$ (9.4)

as $ S$ evolves toward its maximum value.

We can phrase the previous argument in more explicit statistical terms. Suppose that an isolated system is described by a parameter $ y$ (or by several such parameters), but that its total energy is constant. Let $ {\mit\Omega}(y)$ denote the number of microstates accessible to the system when this parameter lies between $ y$ and $ y+\delta y$ ($ \delta y$ being some fixed small interval). The corresponding entropy of the system is $ S=k \ln {\mit\Omega}$ . (See Section 5.6.) If the parameter $ y$ is free to vary then the principle of equal a priori probabilities asserts that, in an equilibrium state, the probability, $ P(y)$ , of finding the system with the parameter between $ y$ and $ y+\delta y$ is given by

$\displaystyle P(y)\propto {\mit\Omega} (y)= \exp\left[\frac{S(y)}{k}\right].$ (9.5)

(See Section 3.3.) The previous expression shows explicitly that the most probable state is one in which $ S$ attains a maximum value, and also allows us to determine the relative probability of fluctuations about this state.


next up previous
Next: Equilibrium of Constant-Temperature System Up: Multi-Phase Systems Previous: Introduction
Richard Fitzpatrick 2016-01-25