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Worked Example 4: AC generators

Question: A simple AC generator consists of an $N=10$ turn coil of area $A= 1200\,{\rm cm}^2$ which rotates at a constant frequency of $f=60$Hz in a $B=0.40$T magnetic field. What is the peak emf of the device?
Answer: The peak emf ${\cal E}_{\rm max}$ is given by [see Eq. (212)]

{\cal E}_{\rm max} = 2\pi\,N\,B\,A\,f = (6.283)\,(10)\,(0.40)\,(0.12)\,(60) = 181 \,{\rm V}.

Richard Fitzpatrick 2007-07-14