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Kepler's First Law

Our planet's radial equation of motion, (303), can be combined with Eq. (322) to give
\begin{displaymath}
\ddot{r} -\frac{h^2}{r^3}= - \frac{G\,M}{r^2}.
\end{displaymath} (325)

Suppose that $r = u^{-1}$. It follows that
\begin{displaymath}
\dot{r} = - \frac{\dot{u}}{u^2} = - r^2\,\frac{du}{d\theta}\,\frac{d\theta}{dt} = - h\,\frac{du}{d\theta}.
\end{displaymath} (326)

Likewise,
\begin{displaymath}
\ddot{r} = - h \,\frac{d^2 u}{d\theta^2}\,\dot{\theta} = - u^2\,h^2\,\frac{d^2 u}{d\theta^2}.
\end{displaymath} (327)

Hence, Eq. (325) can be written
\begin{displaymath}
\frac{d^2 u}{d\theta^2} + u = \frac{G\,M}{h^2}.
\end{displaymath} (328)

The general solution to the above equation takes the form
\begin{displaymath}
u(\theta) = \frac{G\,M}{h^2}\left[1 - e\,\cos(\theta-\theta_0)\right],
\end{displaymath} (329)

where $e$ and $\theta_0$ are arbitrary constants. Without loss of generality, we can set $\theta_0=0$ by rotating our coordinate system about the $z$-axis. Thus, we obtain
\begin{displaymath}
r(\theta) = \frac{r_c}{1 - e\,\cos\theta},
\end{displaymath} (330)

where
\begin{displaymath}
r_c = \frac{h^2}{G\,M}.
\end{displaymath} (331)

We immediately recognize Eq. (330) as the equation of a conic section which is confocal with the origin (i.e., with the Sun). Specifically, for $e<1$, Eq. (330) is the equation of an ellipse which is confocal with the Sun. Thus, the orbit of our planet around the Sun in a confocal ellipse--this is Kepler's first law of planetary motion. Of course, a planet cannot have a parabolic or a hyperbolic orbit, since such orbits are only appropriate to objects which are ultimately able to escape from the Sun's gravitational field.


next up previous contents
Next: Kepler's Third Law Up: Planetary Motion Previous: Kepler's Second Law   Contents
Richard Fitzpatrick 2008-01-13