Infinite Potential Well

Consider a particle of mass $m$ and energy $E$ moving in the following simple potential:

$$V(x) = \left\{\begin{array}{lcl} 0&\mbox{\hspace{1cm}}&\mbox... ...leq a$}\ [0.5ex] \infty&&\mbox{otherwise} \end{array}\right..$$ (302)

It follows from Eq. (301) that if $d^2\psi/d x^2$ (and, hence, $\psi$) is to remain finite then $\psi$ must go to zero in regions where the potential is infinite. Hence, $\psi=0$ in the regions $x\leq 0$ and $x\geq a$. Evidently, the problem is equivalent to that of a particle trapped in a one-dimensional box of length $a$. The boundary conditions on $\psi$ in the region $0<x<a$ are

$$\psi(0) = \psi(a) = 0.$$ (303)

Furthermore, it follows from Eq. (301) that $\psi$ satisfies

$$\frac{d^2 \psi}{d x^2} = - k^2 \psi$$ (304)

in this region, where

$$k^2 = \frac{2 m E}{\hbar^2}.$$ (305)

Here, we are assuming that $E>0$. It is easily demonstrated that there are no solutions with $E<0$ which are capable of satisfying the boundary conditions (303).

The solution to Eq. (304), subject to the boundary conditions (303), is

$$\psi_n(x) = A_n \sin(k_n x),$$ (306)

where the $A_n$ are arbitrary (real) constants, and

$$k_n = \frac{n \pi}{a},$$ (307)

for $n=1,2,3,\cdots$. Now, it can be seen from Eqs. (305) and (307) that the energy $E$ is only allowed to take certain discrete values: i.e.,

$$E_n = \frac{n^2 \pi^2 \hbar^2}{2 m a^2}.$$ (308)

In other words, the eigenvalues of the energy operator are discrete. This is a general feature of bounded solutions: i.e., solutions in which $\vert\psi\vert\rightarrow 0$ as $\vert x\vert\rightarrow\infty$. According to the discussion in Sect. 4.12, we expect the stationary eigenfunctions $\psi_n(x)$ to satisfy the orthonormality constraint

$$\int_0^a \psi_n(x) \psi_m(x) dx = \delta_{nm}.$$ (309)

It is easily demonstrated that this is the case, provided $A_n = \sqrt{2/a}$. Hence,

$$\psi_n(x) = \sqrt{\frac{2}{a}} \sin\left(n \pi \frac{x}{a}\right)$$ (310)

for $n=1,2,3,\cdots$.

Finally, again from Sect. 4.12, the general time-dependent solution can be written as a linear superposition of stationary solutions:

$$\psi(x,t) = \sum_{n=0,\infty} c_n \psi_n(x) {\rm e}^{-{\rm i} E_n t/\hbar},$$ (311)

where

$$c_n = \int_0^a\psi_n(x) \psi(x,0) dx.$$ (312)