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Next: The optical theorem Up: Scattering theory Previous: The Born approximation

Partial waves

We can assume, without loss of generality, that the incident wave-function is characterized by a wave-vector ${\bf k}$ which is aligned parallel to the $z$-axis. The scattered wave-function is characterized by a wave-vector ${\bf k}'$ which has the same magnitude as ${\bf k}$, but, in general, points in a different direction. The direction of ${\bf k}'$ is specified by the polar angle $\theta$ (i.e., the angle subtended between the two wave-vectors), and an azimuthal angle $\varphi$ about the $z$-axis. Equation (928) strongly suggests that for a spherically symmetric scattering potential [i.e., $V({\bf r}) = V(r)$] the scattering amplitude is a function of $\theta$ only:
\begin{displaymath}
f(\theta, \varphi) = f(\theta).
\end{displaymath} (941)

It follows that neither the incident wave-function,
\begin{displaymath}
\phi({\bf r}) = \frac{\exp( {\rm i} k z)}{(2\pi)^{3/2}}= \frac{\exp( {\rm i} k r\cos\theta)}{(2\pi)^{3/2}},
\end{displaymath} (942)

nor the total wave-function,
\begin{displaymath}
\psi({\bf r}) = \frac{1}{(2\pi)^{3/2}}
\left[ \exp( {\rm i}...
...theta) + \frac{\exp( {\rm i} k r)  f(\theta)}
{r} \right],
\end{displaymath} (943)

depend on the azimuthal angle $\varphi$.

Outside the range of the scattering potential, both $\phi({\bf r})$ and $\psi({\bf r})$ satisfy the free space Schrödinger equation

\begin{displaymath}
(\nabla^2 + k^2) \psi = 0.
\end{displaymath} (944)

What is the most general solution to this equation in spherical polar coordinates which does not depend on the azimuthal angle $\varphi$? Separation of variables yields
\begin{displaymath}
\psi(r,\theta) = \sum_l R_l(r)  P_l(\cos\theta),
\end{displaymath} (945)

since the Legendre functions $P_l(\cos\theta)$ form a complete set in $\theta$-space. The Legendre functions are related to the spherical harmonics introduced in Sect. 5 via
\begin{displaymath}
P_l(\cos\theta) = \sqrt{\frac{4\pi}{2 l+1}}  Y_l^0(\theta,\varphi).
\end{displaymath} (946)

Equations (944) and (945) can be combined to give
\begin{displaymath}
r^2\frac{d^2 R_l}{dr^2} + 2 r \frac{dR_l}{dr} + [k^2  r^2 -
l (l+1)]R_l = 0.
\end{displaymath} (947)

The two independent solutions to this equation are called a spherical Bessel function, $j_l(k r)$, and a Neumann function, $\eta_l(k r)$. It is easily demonstrated that
$\displaystyle j_l(y)$ $\textstyle =$ $\displaystyle y^l\left(-\frac{1}{y}\frac{d}{dy}\right)^l \frac{\sin y}{y},$ (948)
$\displaystyle \eta_l(y)$ $\textstyle =$ $\displaystyle -y^l\left(-\frac{1}{y}\frac{d}{dy}\right)^l \frac{\cos y}{y}.$ (949)

Note that spherical Bessel functions are well-behaved in the limit $y\rightarrow 0$ , whereas Neumann functions become singular. The asymptotic behaviour of these functions in the limit $y\rightarrow \infty$ is
$\displaystyle j_l(y)$ $\textstyle \rightarrow$ $\displaystyle \frac{\sin(y - l \pi/2)}{y},$ (950)
$\displaystyle \eta_l(y)$ $\textstyle \rightarrow$ $\displaystyle - \frac{\cos(y-l \pi/2)}{y}.$ (951)

We can write

\begin{displaymath}
\exp( {\rm i} k r \cos\theta) = \sum_l a_l  j_l(k r)  P_l(\cos\theta),
\end{displaymath} (952)

where the $a_l$ are constants. Note there are no Neumann functions in this expansion, because they are not well-behaved as $r\rightarrow 0$. The Legendre functions are orthonormal,
\begin{displaymath}
\int_{-1}^1 P_n(\mu)  P_m(\mu) d\mu = \frac{\delta_{nm}}{n+1/2},
\end{displaymath} (953)

so we can invert the above expansion to give
\begin{displaymath}
a_l  j_l(k r) = (l+1/2)\int_{-1}^1 \exp( {\rm i} k r  \mu)  P_l(\mu)  d\mu.
\end{displaymath} (954)

It is well-known that
\begin{displaymath}
j_l(y) = \frac{(-{\rm i})^l}{2} \int_{-1}^1 \exp( {\rm i}  y \mu)
 P_l(\mu) d\mu,
\end{displaymath} (955)

where $l=0, 1, 2, \cdots$ [see Abramowitz and Stegun (Dover, New York NY, 1965), Eq. 10.1.14]. Thus,
\begin{displaymath}
a_l = {\rm i}^l  (2 l+1),
\end{displaymath} (956)

giving
\begin{displaymath}
\exp( {\rm i} k r \cos\theta) = \sum_l {\rm i}^l 
(2 l+1)  j_l(k r)  P_l(\cos\theta).
\end{displaymath} (957)

The above expression tells us how to decompose a plane-wave into a series of spherical-waves (or ``partial waves'').

The most general solution for the total wave-function outside the scattering region is

\begin{displaymath}
\psi({\bf r}) = \frac{1}{(2\pi)^{3/2}} \sum_l\left[
A_l j_l(k r) + B_l \eta_l(k r)\right] P_l(\cos\theta),
\end{displaymath} (958)

where the $A_l$ and $B_l$ are constants. Note that the Neumann functions are allowed to appear in this expansion, because its region of validity does not include the origin. In the large-$r$ limit, the total wave-function reduces to
\begin{displaymath}
\psi ({\bf r} ) \simeq \frac{1}{(2\pi)^{3/2}} \sum_l\left[A_...
..._l \frac{\cos(k r -l \pi/2)}{k r}
\right] P_l(\cos\theta),
\end{displaymath} (959)

where use has been made of Eqs. (950)-(951). The above expression can also be written
\begin{displaymath}
\psi ({\bf r} ) \simeq \frac{1}{(2\pi)^{3/2}} \sum_l C_l 
\frac{\sin(k r - l \pi/2+ \delta_l)}{k r}  P_l(\cos\theta),
\end{displaymath} (960)

where the sine and cosine functions have been combined to give a sine function which is phase-shifted by $\delta_l$.

Equation (960) yields

$\displaystyle \psi({\bf r})$ $\textstyle \simeq$ $\displaystyle \frac{1}{(2\pi)^{3/2}} \sum_l C_l 
\frac{\exp[ {\rm i} (k r -...
.../2+ \delta_l)]
-\exp[-{\rm i} (k r - l \pi/2+ \delta_l)] }{2 {\rm i} k r}$  
    $\displaystyle \mbox{\hspace{2cm}}\times P_l(\cos\theta),$ (961)

which contains both incoming and outgoing spherical-waves. What is the source of the incoming waves? Obviously, they must be part of the large-$r$ asymptotic expansion of the incident wave-function. In fact, it is easily seen that
$\displaystyle \phi({\bf r})$ $\textstyle \simeq$ $\displaystyle \frac{1}{(2\pi)^{3/2}} \sum_l {\rm i}^l 
(2l+1)  \frac{
\exp[ {\rm i} (k r - l \pi/2)]
-\exp[-{\rm i} (k r - l \pi/2)]}{2 {\rm i} k r}$  
    $\displaystyle \mbox{\hspace{2cm}}\times P_l(\cos\theta)$ (962)

in the large-$r$ limit. Now, Eqs. (942) and (943) give
\begin{displaymath}
(2\pi)^{3/2}[\psi({\bf r} )- \phi({\bf r}) ] =
\frac{\exp( {\rm i} k r)}{r} 
f(\theta).
\end{displaymath} (963)

Note that the right-hand side consists only of an outgoing spherical wave. This implies that the coefficients of the incoming spherical waves in the large-$r$ expansions of $\psi({\bf r})$ and $\phi({\bf r})$ must be equal. It follows from Eqs. (961) and (962) that
\begin{displaymath}
C_l = (2 l+1) \exp[ {\rm i} (\delta_l + l \pi/2)].
\end{displaymath} (964)

Thus, Eqs. (961)-(963) yield
\begin{displaymath}
f(\theta) = \sum_{l=0}^\infty (2 l+1) \frac{\exp( {\rm i} \delta_l)}
{k}  \sin\delta_l P_l(\cos\theta).
\end{displaymath} (965)

Clearly, determining the scattering amplitude $f(\theta)$ via a decomposition into partial waves (i.e., spherical-waves) is equivalent to determining the phase-shifts $\delta_l$.


next up previous
Next: The optical theorem Up: Scattering theory Previous: The Born approximation
Richard Fitzpatrick 2006-02-16