Zero-velocity surfaces

Consider the surface

$\displaystyle V(x,y,z) = C,$ (9.60)

where

$\displaystyle V(x,y,z) = - 2\,U = \frac{2\,\mu_1}{\rho_1}
+ \frac{2\,\mu_2}{\rho_2} +x^{\,2}+y^{\,2}.$ (9.61)

Note that $V\geq 0$. It follows, from Equation (9.35), that if the mass $m_3$ has the Jacobi integral $C$ and lies on the surface specified in Equation (9.60), then it must have zero velocity. Hence, such a surface is termed a zero-velocity surface. The zero-velocity surfaces are important because they form the boundary of regions from which the mass $m_3$ is dynamically excluded; that is, regions where $V< C$. Generally speaking, the regions from which $m_3$ is excluded grow in area as $C$ increases, and vice versa.

Let $C_i$ be the value of $V$ at the $L_i$ Lagrange point, for $i=1,5$. When $\mu_2\ll 1$, it is easily demonstrated that

$\displaystyle C_1$ $\displaystyle \simeq 3 + 3^{4/3}\,\mu_2^{\,2/3}-\frac{10}{3}\,\mu_2,$ (9.62)
$\displaystyle C_2$ $\displaystyle \simeq 3 + 3^{4/3}\,\mu_2^{\,2/3}-\frac{14}{3}\,\mu_2,$ (9.63)
$\displaystyle C_3$ $\displaystyle \simeq 3 + \mu_2,$ (9.64)
$\displaystyle C_4$ $\displaystyle \simeq 3 - \mu_2,$ (9.65)
$\displaystyle C_5$ $\displaystyle \simeq 3 - \mu_2.$ (9.66)

Note that $C_1>C_2>C_3>C_4=C_5$.

Figure: 9.7 Zero-velocity surface $V=C$, where $C> C_1$, calculated for $\mu _2=0.1$. Mass $m_3$ is excluded from the black region.
\includegraphics[height=3.25in]{Chapter08/fig8_07.eps}

Figure: 9.8 Zero-velocity surface $V=C$, where $C= C_1$, calculated for $\mu _2=0.1$. Mass $m_3$ is excluded from the black region.
\includegraphics[height=3.25in]{Chapter08/fig8_08.eps}

Figure: 9.9 Zero-velocity surface $V=C$, where $C= C_2$, calculated for $\mu _2=0.1$. Mass $m_3$ is excluded from the black region.
\includegraphics[height=3.25in]{Chapter08/fig8_09.eps}

Figure: 9.10 Zero-velocity surface $V=C$, where $C =C_3$, calculated for $\mu _2=0.1$. Mass $m_3$ is excluded from the back region.
\includegraphics[height=3.25in]{Chapter08/fig8_10.eps}

Figure: 9.11 Zero-velocity surface $V=C$, where $C_4< C < C_3$, calculated for $\mu _2=0.1$. Mass $m_3$ is excluded from the black regions.
\includegraphics[height=3.25in]{Chapter08/fig8_11.eps}

Figures 9.7 through 9.11 show the intersection of the zero-velocity surface $V=C$ with the $x$-$y$ plane for various different values of $C$, and illustrate how the region from which $m_3$ is dynamically excluded—which we shall term the excluded region—evolves as the value of $C$ is varied. Of course, any point not in the excluded region is in the so-called allowed region. For $C> C_1$, the allowed region consists of two separate oval regions centered on $m_1$ and $m_2$, respectively, plus an outer region that lies beyond a large circle centered on the origin. All three allowed regions are separated from one another by an excluded region. See Figure 9.7. When $C= C_1$, the two inner allowed regions merge at the $L_1$ point. See Figure 9.8. When $C= C_2$, the inner and outer allowed regions merge at the $L_2$ point, forming a horseshoe-like excluded region. See Figure 9.9. When $C =C_3$, the excluded region splits in two at the $L_3$ point. See Figure 9.10. For $C_4< C < C_3$, the two excluded regions are localized about the $L_4$ and $L_5$ points. See Figure 9.11. Finally, for $C < C_4$, there is no excluded region.

Figure: 9.12 Zero-velocity surfaces and Lagrange points calculated for $\mu _2=0.01$.
\includegraphics[height=4in]{Chapter08/fig8_12.eps}

Figure 9.12 shows the zero-velocity surfaces and Lagrange points calculated for the case $\mu _2=0.01$. It can be seen that, at very small values of $\mu _2$, the $L_1$ and $L_2$ Lagrange points are almost equidistant from mass $m_2$. Furthermore, mass $m_2$, and the $L_3$, $L_4$, and $L_5$ Lagrange points all lie approximately on a unit circle, centered on mass $m_1$. It follows that, when $\mu _2$ is small, the Lagrange points $L_3$, $L_4$ and $L_5$ all share the orbit of mass $m_2$ about $m_1$ (in the inertial frame) with $C_3$ being directly opposite $m_2$, $L_4$ (by convention) $60^\circ$ ahead of $m_2$, and $L_5$ $60^\circ$ behind.