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Illustrative Example

Consider a very simple gas made up of two identical particles. Suppose that each particle can be in one of three possible quantum states, $ s=1,2,3$ . Let us enumerate the possible states of the whole gas according to Maxwell-Boltzmann, Bose-Einstein, and Fermi-Dirac statistics, respectively.

For the case of Maxwell-Boltzmann statistics, the two particles are considered to be distinguishable. Let us denote them $ A$ and $ B$ . Furthermore, any number of particles can occupy the same quantum state. The possible different states of the gas are shown in Table 8.1. There are clearly nine distinct states.


Table 8.1: Two particles distributed amongst three states according to Maxwell-Boltzmann statistics.
1 2 3
$ AB$ $ \cdots$ $ \cdots$
$ \cdots$ $ AB$ $ \cdots$
$ \cdots$ $ \cdots$ $ AB$
$ A$ $ B$ $ \cdots$
$ B$ $ A$ $ \cdots$
$ A$ $ \cdots$ $ B$
$ B$ $ \cdots$ $ A$
$ \cdots$ $ A$ $ B$
$ \cdots$ $ B$ $ A$


For the case of Bose-Einstein statistics, the two particles are considered to be indistinguishable. Let us denote them both as $ A$ . Furthermore, any number of particles can occupy the same quantum state. The possible different states of the gas are shown in Table 8.2. There are clearly six distinct states.


Table 8.2: Two particles distributed amongst three states according to Bose-Einstein statistics.
1 2 3
$ AA$ $ \cdots$ $ \cdots$
$ \cdots$ $ AA$ $ \cdots$
$ \cdots$ $ \cdots$ $ AA$
$ A$ $ A$ $ \cdots$
$ A$ $ \cdots$ $ A$
$ \cdots$ $ A$ $ A$


Finally, for the case of Fermi-Dirac statistics, the two particles are considered to be indistinguishable. Let us again denote them both as $ A$ . Furthermore, no more than one particle can occupy a given quantum state. The possible different states of the gas are shown in Table 8.3. There are clearly only three distinct states.


Table 8.3: Two particles distributed amongst three states according to Fermi-Dirac statistics.
1 2 3
$ A$ $ A$ $ \cdots$
$ A$ $ \cdots$ $ A$
$ \cdots$ $ A$ $ A$


It follows, from the previous example, that Fermi-Dirac (FD) statistics are more restrictive (i.e., there are less possible states of the system) than Bose-Einstein (BE) statistics, which are, in turn, more restrictive than Maxwell-Boltzmann (MB) statistics. Let

$\displaystyle \xi = \frac{\mbox{ probability that the two particles are found i...
...te}}{\mbox{ probability that the two particles are found in different states}}.$ (8.12)

For the case under investigation,

$\displaystyle \xi_{\rm MB}$ $\displaystyle = 1/2,$ (8.13)
$\displaystyle \xi_{\rm BE}$ $\displaystyle =1,$ (8.14)
$\displaystyle \xi_{\rm FD}$ $\displaystyle = 0.$ (8.15)

We conclude that in Bose-Einstein statistics there is a greater relative tendency for particles to cluster in the same state than in classical (i.e., Maxwell-Boltzmann) statistics. On the other hand, in Fermi-Dirac statistics there is a lesser tendency for particles to cluster in the same state than in classical statistics.


next up previous
Next: Formulation of Statistical Problem Up: Quantum Statistics Previous: Symmetry Requirements in Quantum
Richard Fitzpatrick 2016-01-25