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Cartesian Components of a Vector

Consider a Cartesian coordinate system $Oxyz$ consisting of an origin, $O$, and three mutually perpendicular coordinate axes, $Ox$, $Oy$, and $Oz$--see Figure A.99. Such a system is said to be right-handed if, when looking along the $Oz$ direction, a $90^\circ$ clockwise rotation about $Oz$ is required to take $Ox$ into $Oy$. Otherwise, it is said to be left-handed. In physics, it is conventional to always use right-handed coordinate systems.

Figure A.99: A right-handed Cartesian coordinate system.
\begin{figure} \epsfysize =1.75in \centerline{\epsffile{AppendixA/figA.02b.eps}} \end{figure}

It is convenient to define unit vectors, ${\bf e}_x$, ${\bf e}_y$, and ${\bf e}_z$, parallel to $Ox$, $Oy$, and $Oz$, respectively. Incidentally, a unit vector is a vector whose magnitude is unity. The position vector, ${\bf r}$, of some general point $P$ whose Cartesian coordinates are ($x$, $y$, $z$) is then given by

\begin{displaymath} {\bf r} = x\,{\bf e}_z + y\,{\bf e}_y+z\,{\bf e}_z. \end{displaymath} (1271)

In other words, we can get from $O$ to $P$ by moving a distance $x$ parallel to $Ox$, then a distance $y$ parallel to $Oy$, and then a distance $z$ parallel to $Oz$. Similarly, if ${\bf a}$ is an arbitrary vector then
\begin{displaymath} {\bf a} = a_x\,{\bf e}_x+ a_y\,{\bf e}_y+a_z\,{\bf e}_z, \end{displaymath} (1272)

where $a_x$, $a_y$, and $a_z$ are termed the Cartesian components of ${\bf a}$. It is coventional to write ${\bf a} \equiv (a_x,\,a_y,\,a_z)$. It follows that ${\bf e}_x\equiv (1,\,0,\,0)$, ${\bf e}_y\equiv (0,\,1,\,0)$, and ${\bf e}_z\equiv (0,\,0,\,1)$. Of course, ${\bf0} \equiv (0,\,0,\,0)$.

According to the three-dimensional generalization of the Pythagorean theorem, the distance $OP\equiv \vert{\bf r}\vert=r$ is given by

\begin{displaymath} r = \sqrt{x^2 + y^2 + z^2}. \end{displaymath} (1273)

By analogy, the magnitude of a general vector ${\bf a}$ takes the form
\begin{displaymath} a = \sqrt{a_x^{\,2} + a_y^{\,2} + a_z^{\,2}}. \end{displaymath} (1274)

If ${\bf a} \equiv (a_x,\,a_y,\,a_z)$ and ${\bf b}\equiv (b_x,\,b_y,\,b_z)$ then it is easily demonstrated that

\begin{displaymath} {\bf a} + {\bf b} \equiv (a_x+b_x,\,a_y+b_y,\,a_z+b_z). \end{displaymath} (1275)

Furthermore, if $n$ is a scalar then it is apparent that
\begin{displaymath} n\,{\bf a} \equiv (n\,a_x,\,n\,a_y,\,n\,a_z). \end{displaymath} (1276)

next up previous
Next: Coordinate Transformations Up: Vector Algebra and Vector Previous: Vector Algebra
Richard Fitzpatrick 2011-03-31