Moment of Inertia Tensor

Consider a rigid body rotating with fixed angular velocity $\omega$ about an axis which passes through the origin--see Figure 28. Let ${\bf r}_i$ be the position vector of the $i$th mass element, whose mass is $m_i$. We expect this position vector to precess about the axis of rotation (which is parallel to $\omega$) with angular velocity $\omega$. It, therefore, follows from Equation (A.1309) that

$$\frac{d{\bf r}_i}{dt} = \mbox{\boldmath$\omega$}\times {\bf r}_i.$$ (457)

Thus, the above equation specifies the velocity, ${\bf v}_i = d{\bf r}_i/dt$, of each mass element as the body rotates with fixed angular velocity $\omega$ about an axis passing through the origin.

Figure 28: A rigid rotating body.

The total angular momentum of the body (about the origin) is written

$${\bf L} = \sum_{i=1,N} m_i\,{\bf r}_i\times\frac{d{\bf r}_i}... ...}- ({\bf r}_i\cdot\mbox{\boldmath$\omega$})\,{\bf r}_i\right],$$ (458)

where use has been made of Equation (457), and some standard vector identities (see Section A.10). The above formula can be written as a matrix equation of the form

$$\left(\begin{array}{c}L_x\\ L_y\\ L_z\end{array}\right)= \le... ...gin{array}{c}\omega_x\\ \omega_y\\ \omega_z\end{array}\right),$$ (459)

where

$$I_{xx} = \sum_{i=1,N}(y_i^{\,2}+z_i^{\,2}) \,m_i= \int(y^2+ z^2)\,dm,$$ (460)

$$I_{yy} = \sum_{i=1,N}(x_i^{\,2}+z_i^{\,2}) \,m_i= \int(x^2+ z^2)\,dm,$$ (461)

$$I_{zz} = \sum_{i=1,N}(x_i^{\,2}+y_i^{\,2}) \,m_i= \int(x^2+ y^2)\,dm,$$ (462)

$$I_{xy}=I_{yx} = - \sum_{i=1,N}x_i\,y_i \,m_i=- \int x\,y\,dm,$$ (463)

$$I_{yz}=I_{zy} = - \sum_{i=1,N}y_i\,z_i \,m_i= -\int y\,z\,dm,$$ (464)

$$I_{xz}=I_{zx} = - \sum_{i=1,N}x_i\,z_i \,m_i= -\int x\,z\,dm.$$ (465)

Here, $I_{xx}$ is called the moment of inertia about the $x$-axis, $I_{yy}$ the moment of inertia about the $y$-axis, $I_{xy}$ the $xy$ product of inertia, $I_{yz}$ the $yz$ product of inertia, etc. The matrix of the $I_{ij}$ values is known as the moment of inertia tensor. Note that each component of the moment of inertia tensor can be written as either a sum over separate mass elements, or as an integral over infinitesimal mass elements. In the integrals, $dm = \rho\,dV$, where $\rho$ is the mass density, and $dV$ a volume element. Equation (459) can be written more succinctly as

$${\bf L} = \tilde{\bf I}\,\mbox{\boldmath$\omega$}.$$ (466)

Here, it is understood that ${\bf L}$ and $\omega$ are both column vectors, and $\tilde{\bf I}$ is the matrix of the $I_{ij}$ values. Note that $\tilde{\bf I}$ is a real symmetric matrix: i.e., $I_{ij}^{\,\ast} = I_{ij}$ and $I_{ji} = I_{ij}$.

In general, the angular momentum vector, ${\bf L}$, obtained from Equation (466), points in a different direction to the angular velocity vector, $\omega$. In other words, ${\bf L}$ is generally not parallel to $\omega$.

Finally, although the above results were obtained assuming a fixed angular velocity, they remain valid at each instant in time if the angular velocity varies.