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Vector Line Integrals

A vector field is defined as a set of vectors associated with each point in space. For instance, the velocity $ {\bf v}({\bf r})$ in a moving liquid (e.g., a whirlpool) constitutes a vector field. By analogy, a scalar field is a set of scalars associated with each point in space. An example of a scalar field is the temperature distribution $ T({\bf r})$ in a furnace.

Consider a general vector field $ {\bf A}({\bf r})$ . Let $ d{\bf r} \equiv (dx,\,dy,\,dz)$ be the vector element of line length. Vector line integrals often arise as

$\displaystyle \int_P^Q {\bf A}\cdot d{\bf r} = \int_P^Q (A_x\,dx+A_y\,dy + A_z\,dz).$ (A.81)

For instance, if $ {\bf A}$ is a force-field then the line integral is the work done in going from $ P$ to $ Q$ .

For example, consider the work done by a repulsive inverse-square central field, $ {\bf F} = - {\bf r}/ \vert r^{\,3}\vert$ . The element of work done is $ dW={\bf F}\cdot d{\bf r}$ . Take $ P=(\infty, 0, 0)$ and $ Q=(a,0,0)$ . The first route considered is along the $ x$ -axis, so

$\displaystyle W = \int_{\infty}^a \left(-\frac{1}{x^{\,2}}\right)\,dx = \left[\frac{1}{x}\right]_{\infty}^a =\frac{1}{a}.$ (A.82)

The second route is, firstly, around a large circle ($ r=$ constant) to the point ($ a$ , $ \infty $ , 0), and then parallel to the $ y$ -axis. (See Figure A.16). In the first part, no work is done, because $ {\bf F}$ is perpendicular to $ d{\bf r}$ . In the second part,

$\displaystyle W = \int_{\infty}^0 \frac{-y\,dy}{(a^{\,2} + y^{\,2})^{3/2}} = \left[\frac{1}{(y^{\,2}+a^{\,2})^{1/2}} \right]^0_\infty = \frac{1}{a}.$ (A.83)

In this case, the integral is independent of the path. However, not all vector line integrals are path independent.

Figure A.16: An example vector line integral.
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next up previous
Next: Surface Integrals Up: Vectors and Vector Fields Previous: Line Integrals
Richard Fitzpatrick 2016-03-31