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Next: Worked example 11.2: Block Up: Oscillatory motion Previous: Uniform circular motion

Worked example 11.1: Piston in steam engine

Question: A piston in a stream engine executes simple harmonic motion. Given that the maximum displacement of the piston from its centre-line is $\pm 7 {\rm cm}$, and that the mass of the piston is $4 {\rm kg}$, find the maximum velocity of the piston when the steam engine is running at 4000rev./min. What is the maximum acceleration?

Answer: We are told that the amplitude of the oscillation is $a=0.07 {\rm m}$. Moreover, when converted to cycles per second (i.e., hertz), the frequency of the oscillation becomes

\begin{displaymath}
f = \frac{4000}{60} = 66.6666 {\rm Hz}.
\end{displaymath}

Hence, the angular frequency is

\begin{displaymath}
\omega = 2 \pi f = 418.88 {\rm rad./sec}.
\end{displaymath}

Consulting Tab. 4, we note that the maximum velocity of an object executing simple harmonic motion is $v_{\rm max} = a \omega$. Hence, the maximum velocity is

\begin{displaymath}
v_{\rm max} = a \omega = 0.07\times 418.88 = 29.32 {\rm m/s}.
\end{displaymath}

Likewise, according to Tab. 4, the maximum acceleration is given by

\begin{displaymath}
a_{\rm max} = a \omega^2 = 0.07 \times 418.88\times 418.88 = 1.228\times 10^4 {\rm m/s^2}.
\end{displaymath}


next up previous
Next: Worked example 11.2: Block Up: Oscillatory motion Previous: Uniform circular motion
Richard Fitzpatrick 2006-02-02