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# Gaussian Probability Distribution

Consider a very large number of observations, , made on a system with two possible outcomes. Suppose that the probability of outcome 1 is sufficiently large that the average number of occurrences after observations is much greater than unity: that is,

 (2.54)

In this limit, the standard deviation of is also much greater than unity,

 (2.55)

implying that there are very many probable values of scattered about the mean value, . This suggests that the probability of obtaining occurrences of outcome 1 does not change significantly in going from one possible value of to an adjacent value. In other words,

 (2.56)

In this situation, it is useful to regard the probability as a smooth function of . Let be a continuous variable that is interpreted as the number of occurrences of outcome 1 (after observations) whenever it takes on a positive integer value. The probability that lies between and is defined

 (2.57)

where is called the probability density, and is independent of . The probability can be written in this form because can always be expanded as a Taylor series in , and must go to zero as . We can write

 (2.58)

which is equivalent to smearing out the discrete probability over the range . Given Equations (2.38) and (2.56), the previous relation can be approximated as

 (2.59)

For large , the relative width of the probability distribution function is small: that is,

 (2.60)

This suggests that is strongly peaked around the mean value, . Suppose that attains its maximum value at (where we expect ). Let us Taylor expand around . Note that we are expanding the slowly-varying function , rather than the rapidly-varying function , because the Taylor expansion of does not converge sufficiently rapidly in the vicinity of to be useful. We can write

 (2.61)

where

 (2.62)

By definition,

 (2.63) (2.64)

if corresponds to the maximum value of .

It follows from Equation (2.59) that

 (2.65)

If is a large integer, such that , then is almost a continuous function of , because changes by only a relatively small amount when is incremented by unity. Hence,

 (2.66)

giving

 (2.67)

for . The integral of this relation

 (2.68)

valid for , is called Stirling's approximation, after the Scottish mathematician James Stirling, who first obtained it in 1730.

According to Equations (2.62), (2.65), and (2.67),

 (2.69)

Hence, if then

 (2.70)

giving

 (2.71)

because . [See Equations (2.11) and (2.43).] Thus, the maximum of occurs exactly at the mean value of , which equals .

Further differentiation of Equation (2.69) yields [see Equation (2.62)]

 (2.72)

because . Note that , as required. According to Equation (2.55), the previous relation can also be written

 (2.73)

It follows, from the previous analysis, that the Taylor expansion of can be written

 (2.74)

Taking the exponential of both sides, we obtain

 (2.75)

The constant is most conveniently fixed by making use of the normalization condition

 (2.76)

which becomes

 (2.77)

for a continuous distribution function. Because we only expect to be significant when lies in the relatively narrow range , the limits of integration in the previous expression can be replaced by with negligible error. Thus,

 (2.78)

As is well known,

 (2.79)

(See Exercise 1.) It follows from the normalization condition (2.78) that

 (2.80)

Finally, we obtain

 (2.81)

This is the famous Gaussian probability distribution, named after the German mathematician Carl Friedrich Gauss, who discovered it while investigating the distribution of errors in measurements. The Gaussian distribution is only valid in the limits and .

Suppose we were to plot the probability against the integer variable , and then fit a continuous curve through the discrete points thus obtained. This curve would be equivalent to the continuous probability density curve , where is the continuous version of . According to Equation (2.81), the probability density attains its maximum value when equals the mean of , and is also symmetric about this point. In fact, when plotted with the appropriate ratio of vertical to horizontal scalings, the Gaussian probability density curve looks rather like the outline of a bell centered on . Hence, this curve is sometimes called a bell curve. At one standard deviation away from the mean value--that is --the probability density is about 61% of its peak value. At two standard deviations away from the mean value, the probability density is about 13.5% of its peak value. Finally, at three standard deviations away from the mean value, the probability density is only about 1% of its peak value. We conclude that there is very little chance that lies more than about three standard deviations away from its mean value. In other words, is almost certain to lie in the relatively narrow range .

In the previous analysis, we went from a discrete probability function, , to a continuous probability density, . The normalization condition becomes

 (2.82)

under this transformation. Likewise, the evaluations of the mean and variance of the distribution are written

 (2.83)

and

 (2.84)

respectively. These results follow as simple generalizations of previously established results for the discrete function . The limits of integration in the previous expressions can be approximated as because is only non-negligible in a relatively narrow range of . Finally, it is easily demonstrated that Equations (2.82)-(2.84) are indeed true by substituting in the Gaussian probability density, Equation (2.81), and then performing a few elementary integrals. (See Exercise 3.)

Next: Central Limit Theorem Up: Probability Theory Previous: Application to Binomial Probability
Richard Fitzpatrick 2016-01-25