- Demonstrate that the eigenvalues of the two-particle permutation operator,
, are
.
- Derive Equations (9.14) and (9.15).
- Demonstrate that the two-particle permutation operator,
, is Hermitian.
- Justify Equation (9.35).
- Consider the cyclic permutation operator
- Consider two identical spin-
particles of mass
confined in a cubic box of dimension
. Find the possible
energies and wavefunctions of this system in the case of no interaction between the particles.
- Consider a system of two spin-
particles with no orbital angular momentum (i.e., both particles are in the lowest energy
-state). What are
the possible eigenvalues of the total angular momentum of the system, as well as its projection along the
-direction, in the
cases in which the particles are non-identical and identical?
- Consider a hydrogen-like atom consisting of a single electron of charge
orbiting about a massive nucleus
of charge
(where
). The eigenstates of the Hamiltonian can be labelled by the conventional
quantum numbers
,
, and
.
- Show that the energy levels are
- Demonstrate that the first few properly normalized radial wavefunctions,
, take the form:

where is the Bohr radius.

- Show that the energy levels are
- Demonstrate that
- Justify Equation (9.63).
- Given that the ground-state energy of a helium atom is
, deduce that the
ground-state ionization energy (i.e., the minimum energy that must be supplied to remove a single electron from the
atom in the ground-state) is
.
- Consider a helium atom in which both electrons are in the
,
,
state (i.e., the
state). Use the techniques of Section 9.5 to obtain
the following estimate for the energy of this state:
*autoionization*. - Consider an excited state of the helium atom in which one electron is in the ground state, and the other is
in the
state, where
.
- Demonstrate that the expressions for the direct and exchange integrals given
in Section 9.6 reduce to

and

respectively, where is a hydrogen radial wavefunction calculated with a nuclear charge . - Suppose that the excited electron is in the
,
,
state (i.e., the
state). Show that

Hence, deduce that the energies of the states of orthohelium and parahelium are

where the upper sign corresponds to parahelium.

- Demonstrate that the expressions for the direct and exchange integrals given
in Section 9.6 reduce to
- The observed energies of the
states of orthohelium and parahelium are

where the upper sign corresponds to parahelium [77]. It can be seen that the calculation in the previous exercise has considerably overestimated the size of the exchange integral. The main reason for this is that we neglected to take into account the fact that the electron largely shields the electron from the nuclear charge (because, on average, the former electron lies much closer to the nucleus that the latter). We can arrive at a better estimate for the exchange integral by using a radial function calculated with a nuclear charge , and a radial function calculated with a nuclear charge . Here, we are assuming that the inner ( ) electron experiences the full nuclear charge, whereas the outer ( ) electron only experiences half the nuclear charge, as a consequence of the shielding action of the inner electron. Demonstrate that, in this case, the exchange integral becomes - Let
- Consider the general energy eigenvalue problem
- Consider a particle of mass
moving in the one-dimensional potential

Verify that these wavefunctions are properly normalized. Use the variational principle, combined with the plausible trial wavefunctions and (these wavefunctions are, in fact, the exact ground-state and first-excited-state wavefunctions for a particle moving in the potential ) to obtain the following estimates for the energies of the ground state, and the first excited state, of the system:

The exact numerical factors that should appear in the previous two equations are and , respectively [77]. Hence, it is clear that our approximation to and are fairly accurate. - Use the variational technique outlined in Section 9.7 to derive the following estimate the ground-state energy of
a two-electron atom with nuclear charge
in the spin-singlet state:
- It can be seen from Section 9.7, as well as the previous exercise, that the variational
technique described in Section 9.7 yields approximations to the ground-state energies of two-electron
atoms in the spin-singlet state that are approximately
too high. This is not a particular
problem for the helium atom, or the singly-ionized lithium ion. However, for the negative hydrogen
ion, our estimate for the ground-state energy,
, is slightly higher than the ground-state
energy of a neutral hydrogen atom,
, giving the erroneous impression that it is not energetically favorable for
a neutral hydrogen atom to absorb an additional electron to form a negative hydrogen ion (i.e., that the negative hydrogen ion has
a negative binding energy).

Obviously, we need to perform a more accurate calculation for the case of a negative hydrogen ion. Following Chandrasekhar [21], let us adopt the following trial wavefunction:

Here, , is the Bohr radius, and , are adjustable parameters. Moreover, takes the values and for the spin-singlet and spin-triplet states, respectively. Given that the Hamiltonian of a two-electron atom of nuclear charge is

where is the hydrogen ground-state energy, , and . We now need to minimize with respect to variations in and to obtain an estimate for the ground-state energy. Unfortunately, this can only be achieved numerically.The previous table shows the numerically determined values of and that minimize for various choices of and . The table also shows the estimate for the ground-state energy ( ), as well as the corresponding experimentally measured ground-state energy ( ) [63,66]. It can be seen that our new estimate for the ground-state energy of the negative hydrogen ion is now less than the ground-state energy of a neutral hydrogen atom, which demonstrates that the negative hydrogen ion has a positive (albeit, small) binding energy. Incidentally, the case , yields a good estimate for the energy of the lowest-energy spin-triplet state of a helium atom (i.e., the spin-triplet state).

- Justify Equation (9.108).
- Justify Equations (9.116) and (9.117).
- Justify Equations (9.119) and (9.120).
- Repeat the calculation of Section 9.8 using the the trial single-proton wavefunction
It can be shown, numerically, that the previous function attains its minimum value, , when and . This leads to predictions for the equilibrium separation between the two protons, and the binding energy of the molecule, of and , respectively. (See Figure 9.1.) These values are far closer to the experimentally determined values, and [53], than those derived in Section 9.8.