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Next: Resonances Up: Waves in Cold Plasmas Previous: Wave Propagation Through Inhomogeneous


We have seen that electromagnetic wave propagation (in one dimension) through an inhomogeneous plasma, in the physically relevant limit in which the variation length-scale of the plasma is much greater than the wave-length of the wave, is well described by the WKB solutions, (569)-(570). However, these solutions break down in the immediate vicinity of a cutoff, where $n^2=0$, or a resonance, where $n^2\rightarrow\infty$. Let us now examine what happens to electromagnetic waves propagating through a plasma when they encounter a cutoff or a resonance.

Suppose that a cutoff is located at $z=0$, so that

n^2 = a\,z+ O(z^2)
\end{displaymath} (571)

in the immediate vicinity of this point, where $a>0$. It is evident, from the WKB solutions, (569)-(570), that the cutoff point lies at the boundary between a region ($z>0$) in which electromagnetic waves propagate, and a region ($z<0$) in which the waves are evanescent. In a physically realistic solution, we would expect the wave amplitude to decay (as $z$ decreases) in the evanescent region $z<0$. Let us search for such a wave solution.

In the immediate vicinity of the cutoff point, $z=0$, Eqs. (555) and (571) yield

\frac{d^2 E_y}{d\hat{z}^2} + \hat{z}\,E_y = 0,
\end{displaymath} (572)

\hat{z} = (k_0^{~2}\,a)^{1/3}\,z.
\end{displaymath} (573)

Equation (572) is a standard equation, known as Airy's equation, and possesses two independent solutions, denoted ${\rm Ai}(-\hat{z})$ and ${\rm Bi}(-\hat{z})$.[*] The second solution, ${\rm Bi}(-\hat{z})$, is unphysical, since it blows up as $\hat{z}\rightarrow-\infty$. The physical solution, ${\rm Ai}(-\hat{z})$, has the asymptotic behaviour
{\rm Ai}(-\hat{z})\sim \frac{1}{2\,\sqrt{\pi}}\, \vert\hat{z...
\end{displaymath} (574)

in the limit $\hat{z}\rightarrow-\infty$, and
{\rm Ai}(-\hat{z})\sim \frac{1}{\sqrt{\pi}}\, \hat{z}^{-1/4}\,\sin\!
\end{displaymath} (575)

in the limit $\hat{z}\rightarrow +\infty$.

Suppose that a unit amplitude plane electromagnetic wave, polarized in the $y$-direction, is launched from an antenna, located at large positive $z$, towards the cutoff point at $z=0$. It is assumed that $n=1$ at the launch point. In the non-evanescent region, $z>0$, the wave can be represented as a linear combination of propagating WKB solutions:

E_y(z) = n^{-1/2}\,\exp\left(- {\rm i}\, k_0 \!\int_0^z \!n\...
...,n^{-1/2}\,\exp\left(+{\rm i}\, k_0 \!\int_0^z \!n\,dz\right).
\end{displaymath} (576)

The first term on the right-hand side of the above equation represents the incident wave, whereas the second term represents the reflected wave. The complex constant $R$ is the coefficient of reflection. In the vicinity of the cutoff point (i.e., $z$ small and positive, or $\hat{z}$ large and positive) the above expression reduces to
E_y(\hat{z}) = (k_0/a)^{1/6}\,\left[
...xp\!\left(+{\rm i}\,\frac{2}{3}\,\hat{z}^{3/2}\right)
\end{displaymath} (577)

However, we have another expression for the wave in this region. Namely,
E_y(\hat{z}) = C\,{\rm Ai}(-\hat{z}) \simeq \frac{C}{\sqrt{\...
\end{displaymath} (578)

where $C$ is an arbitrary constant. The above equation can be written
E_y(\hat{z}) =\frac{C}{2}\sqrt{\frac{{\rm i}}{\pi}}
...xp\!\left(+{\rm i}\,\frac{2}{3}\,\hat{z}^{3/2}\right)
\end{displaymath} (579)

A comparison of Eqs. (577) and (579) yields
R = -{\rm i}.
\end{displaymath} (580)

In other words, at a cutoff point there is total reflection, since $\vert R\vert=1$, with a $-\pi/2$ phase-shift.

next up previous
Next: Resonances Up: Waves in Cold Plasmas Previous: Wave Propagation Through Inhomogeneous
Richard Fitzpatrick 2011-03-31