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Next: Electromagnetic Energy Tensor Up: Relativity and Electromagnetism Previous: Relativistic Particle Dynamics

Force on a Moving Charge

The electromagnetic 3-force acting on a charge $ e$ moving with 3-velocity $ {\bf u}$ is given by the well-known formula

$\displaystyle {\bf f} = e\,({\bf E} + {\bf u}\times {\bf B}).$ (1851)

When written in component form this expression becomes

$\displaystyle f_i = e\,(E_i + \epsilon_{ijk} \,u^{\,j} \,B^{\,k}),$ (1852)

or

$\displaystyle f_i = e\,(E_i + B_{ij}\, u^{\,j}),$ (1853)

where use has been made of Equation (1766).

Recall that the components of the $ {\bf E}$ and $ {\bf B}$ fields can be written in terms of an antisymmetric electromagnetic field tensor $ F_{\mu\nu}$ via

$\displaystyle F_{i4}$ $\displaystyle =-F_{4i} = -E_i,$ (1854)
$\displaystyle F_{ij}$ $\displaystyle = -F_{ji} = -c\,B_{ij}.$ (1855)

Equation (1855) can be written

$\displaystyle f_i = -\frac{e}{\gamma\,c} \,(F_{i4} \,U^{\,4} + F_{ij}\, U^{\,j}),$ (1856)

where $ U^{\,\mu} = \gamma\,({\bf u}, \,c)$ is the particle's 4-velocity. It is easily demonstrated that

$\displaystyle \frac{{\bf f}\cdot{\bf u}}{c} = \frac{e}{c}\, {\bf E}\cdot{\bf u}...
...c} \,E_i\, u^{\,i} = \frac{e}{\gamma\,c} (F_{4i} \,U^{\,i} + F_{44} \,U^{\,4}).$ (1857)

Thus, the 4-force acting on the particle,

$\displaystyle {\cal F}_\mu = \gamma\left(-{\bf f},\, \frac{{\bf f}\cdot{\bf u}}{c} \right),$ (1858)

can be written in the form

$\displaystyle {\cal F}_\mu = \frac{e}{c}\, F_{\mu\nu}\, U^{\,\nu}.$ (1859)

The skew symmetry of the electromagnetic field tensor ensures that

$\displaystyle {\cal F}_\mu \,U^{\,\mu} = \frac{e}{c}\, F_{\mu\nu}\, U^{\,\mu} \,U^{\,\nu} = 0.$ (1860)

This is an important result, because it ensures that electromagnetic fields do not change the rest mass of charged particles. In order to appreciate this, let us assume that the rest mass $ m_0$ is not a constant. Because

$\displaystyle {\cal F}_\mu =\frac{d(m_0\, U_\mu)}{d\tau} = m_0\, A_\mu + \frac{dm_0}{d\tau} \,U_\mu,$ (1861)

we can use the standard results $ U_\mu\, U^{\,\mu} = c^{\,2}$ and $ A_\mu \,U^{\,\mu} =0$ to give

$\displaystyle {\cal F}_\mu \,U^{\,\mu} = c^{\,2} \,\frac{dm_0}{d\tau}.$ (1862)

Thus, if rest mass is to remain an invariant, it is imperative that all laws of physics predict 4-forces acting on particles that are orthogonal to the particles' instantaneous 4-velocities. The laws of electromagnetism pass this test.


next up previous
Next: Electromagnetic Energy Tensor Up: Relativity and Electromagnetism Previous: Relativistic Particle Dynamics
Richard Fitzpatrick 2014-06-27