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Generalized Forces

The work done on the dynamical system when its Cartesian coordinates change by $\delta x_j$ is simply
\begin{displaymath}
\delta W = \sum_{j=1,{\cal F}} f_j\,\delta x_j
\end{displaymath} (594)

Here, the $f_j$ are the Cartesian components of the forces acting on the various particles making up the system. Thus, $f_1, f_2, f_3$ are the components of the force acting on the first particle, $f_4, f_5, f_6$ the components of the force acting on the second particle, etc. Using Equation (593), we can also write
\begin{displaymath}
\delta W = \sum_{j=1,{\cal F}} f_j\sum_{i=1,{\cal F}}\frac{\partial x_j}{\partial q_i}\,\delta q_i.
\end{displaymath} (595)

The above expression can be rearranged to give
\begin{displaymath}
\delta W = \sum_{i=1,{\cal F}} Q_i\,\delta q_i,
\end{displaymath} (596)

where
\begin{displaymath}
Q_i = \sum_{j=1,{\cal F}} f_j\,\frac{\partial x_j}{\partial q_i}.
\end{displaymath} (597)

Here, the $Q_i$ are termed generalized forces. Note that a generalized force does not necessarily have the dimensions of force. However, the product $Q_i\,q_i$ must have the dimensions of work. Thus, if a particular $q_i$ is a Cartesian coordinate then the associated $Q_i$ is a force. Conversely, if a particular $q_i$ is an angle then the associated $Q_i$ is a torque.

Suppose that the dynamical system in question is conservative. It follows that

\begin{displaymath}
f_j = -\frac{\partial U}{\partial x_j},
\end{displaymath} (598)

for $j=1,{\cal F}$, where $U(x_1,x_2,\cdots,x_{\cal F},t)$ is the system's potential energy. Hence, according to Equation (597),
\begin{displaymath}
Q_i = - \sum_{j=1,{\cal F}} \frac{\partial U}{\partial x_j}\...
...artial x_j}{\partial q_i} = - \frac{\partial U}{\partial q_i},
\end{displaymath} (599)

for $i=1,{\cal F}$.


next up previous
Next: Lagrange's Equation Up: Lagrangian Dynamics Previous: Generalized Coordinates
Richard Fitzpatrick 2011-03-31