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- Consider the case of Rutherford scattering in the event that
. Demonstrate that the differential scattering cross-section in the
laboratory frame is approximately
where
.
- Show that the energy distribution of particles recoiling from an elastic
collision is always directly proportional to the differential scattering cross-section
in the center of mass frame.
- It is found experimentally that in the elastic scattering of neutrons
by protons (
) at relatively low energies, the energy distribution
of the recoiling protons in the laboratory frame is constant up to
a maximum energy, which is the energy of the incident neutrons. What is the
angular distribution of the scattering in the center of mass frame?
- The most energetic
-particles available to Earnst Rutherford and his colleagues for the
famous Rutherford scattering experiment were
MeV. For the scattering of 7.7MeV
-particles from Uranium 238 nuclei (initially at rest) at a scattering angle in the laboratory frame of
, find the following (in the laboratory frame, unless otherwise specified):
- The recoil scattering angle of the Uranium nucleus.
- The scattering angles of the
-particle and Uranium nucleus in the center of mass
frame.
- The kinetic energies of the scattered
-particle and Uranium nucleus (in MeV).
- The impact parameter
.
- The distance of closest approach.
- The differential scattering cross-section at
.
- Consider scattering by the repulsive potential
(where
)
viewed in the center of mass frame. Demonstrate that the differential
scattering cross-section is
Next: Non-Inertial Reference Frames
Up: Two-Body Dynamics
Previous: Scattering in the Laboratory
Contents
Richard Fitzpatrick
2008-01-13