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Simple Harmonic Motion

Consider the motion of an object of mass $m$ which is slightly perturbed from a stable equilibrium point at $x=0$. Suppose that the object is moving in the conservative force-field $f(x)$. According to the analysis in Sect. 4.2, for $x=0$ to be a stable equilibrium point we require both
\begin{displaymath}
f(0) = 0,
\end{displaymath} (161)

and
\begin{displaymath}
\frac{d f(0)}{dx} < 0.
\end{displaymath} (162)

Now, our object obeys Newton's second law of motion,

\begin{displaymath}
m\,\frac{d^2 x}{d t^2} = f(x).
\end{displaymath} (163)

Let us assume that it always stays fairly close to its equilibrium position. In this case, to a good approximation, we can represent $f(x)$ as a truncated Taylor series about this position. In other words,
\begin{displaymath}
f(x) \simeq f(0) + \frac{df(0)}{dx}\,x + O(x^2).
\end{displaymath} (164)

However, according to (161) and (162), the above expression can be written
\begin{displaymath}
f(x) \simeq - m\,\omega_0^{\,2}\,x,
\end{displaymath} (165)

where $df(0)/dx = -m\,\omega_0^{\,2}$. Hence, we conclude that our object satisfies the following approximate equation of motion,
\begin{displaymath}
\frac{d^2 x}{dt^2}+ \omega_0^{\,2}\,x\simeq 0,
\end{displaymath} (166)

provided that it does not stray too far from its equilibrium position ($x=0$).

Equation (166) is called the simple harmonic equation, and governs the motion of all one-dimensional conservative systems which are slightly perturbed from some stable equilibrium point. The solution of Eq. (166) is well-known:

\begin{displaymath}
x(t) = a\,\sin(\omega_0\,t -\phi_0).
\end{displaymath} (167)

The pattern of motion described by above equation, which is called simple harmonic motion, is periodic in time, with repetition period $T_0 = 2\pi/\omega_0$, and oscillates between $x=\pm a$. Here, $a$ is called the amplitude of the motion. The parameter $\phi_0$, known as the phase angle, simply shifts the pattern of motion backward and forward in time. Figure 19 shows examples of simple harmonic motion, Here, $\phi_0 = 0$, $+\pi/4$, and $-\pi/4$ correspond to the solid, short-dashed, and long dashed-curves, respectively.

Note that the frequency, $\omega_0$--and, hence, the period, $T_0$--of simple harmonic motion is determined by the parameters in the simple harmonic equation, (166). However, the amplitude, $a$, and the phase angle, $\phi_0$, are the two constants of integration of this second-order differential equation, and are, thus, determined by the initial conditions: i.e., by the object's initial displacement and velocity.

Figure 19: Simple harmonic motion.
\begin{figure}
\epsfysize =3in
\centerline{\epsffile{shm.eps}}
\end{figure}

Now, from Eqs. (136) and (165), the potential energy of our object at position $x$ is approximately

\begin{displaymath}
U(x) \simeq \frac{1}{2}\,m\,\omega_0^{\,2}\,x^2.
\end{displaymath} (168)

Hence, the total energy is written
\begin{displaymath}
E = K + U = \frac{1}{2}\,m\left(\frac{dx}{dt}\right)^2+ \frac{1}{2}\,m\,\omega_0^{\,2}\,x^2,
\end{displaymath} (169)

giving
\begin{displaymath}
E = \frac{1}{2}\,m\,\omega_0^{\,2}\,a^2\,\cos^2(\omega_0\,t-...
...n^2(\omega_0\,t-\phi_0)
= \frac{1}{2}\,m\,\omega_0^{\,2}\,a^2,
\end{displaymath} (170)

where use has been made of Eq. (167), and the trigonometric identity $\cos^2\theta+\sin^2\theta \equiv 1$. Note that the total energy is constant in time, as is to be expected for a conservative system, and is proportional to the amplitude squared of the motion.


next up previous contents
Next: Damped Oscillatory Motion Up: One-Dimensional Motion Previous: Velocity Dependent Forces   Contents
Richard Fitzpatrick 2008-01-13