d'Alembert's Paradox

Consider two cross-sections, and , a great distance upstream and downstream of , respectively. The fluid between these sections can be split into a great many stream filaments to each of which Euler's momentum theorem is applicable. The outer filaments are bounded by the walls of the tube, and so the thrust components acting on these are directed perpendicular to the flow. The walls of the filaments in contact with are acted on by the obstacle, which exerts on them a force whose component in the direction of the flow is . By Euler's theorem, the resultant of all of the thrusts acting on the fluid in the tube is

(4.11) |

which vanishes, because .

By Bernoulli's theorem, the pressure acting across is the same as the pressure acting across . Thus, according to Euler's theorem,

(4.12) |

which implies that

(4.13) |

The surprising result that the net parallel force exerted by an inviscid fluid stream on a stationary obstacle placed in its path is zero is known as

If we suppose the walls of the tube to recede to infinity then we obtain the case of an obstacle immersed in a moving stream that is unbounded in every direction. The previous proof still shows that .

Finally, if we impose on the whole system a uniform velocity in the direction opposite to that of the stream then the fluid at a great distance is reduced to rest, and the obstacle moves with the uniform speed . However, superposing a uniform flow does not alter the dynamical conditions. Therefore, we conclude that the resistance to a solid body moving with uniform velocity through an unbounded inviscid fluid, otherwise at rest, is zero.