Alpha Decay

Many types of heavy atomic nuclei spontaneously decay to produce daughter nuclei via the emission of $\alpha $-particles (i.e., helium nuclei) of some characteristic energy. This process is known as $\alpha $-decay. Let us investigate the $\alpha $-decay of a particular type of atomic nucleus of radius $R$, charge-number $Z$, and mass-number $A$. Such a nucleus thus decays to produce a daughter nucleus of charge-number $Z_1=Z-2$ and mass-number $A_1=A-4$, and an $\alpha $-particle of charge-number $Z_2=2$ and mass-number $A_2=4$. Let the characteristic energy of the $\alpha $-particle be $E$. Incidentally, nuclear radii are found to satisfy the empirical formula

$\displaystyle R = 1.5\times 10^{-15}\,A^{1/3}\,{\rm m}=2.0\times 10^{-15}\,Z_1^{\,1/3}\,{\rm m}$ (11.132)

for $Z\gg 1$ (Park 1974).

In 1928, George Gamov proposed a very successful theory of $\alpha $-decay, according to which the $\alpha $-particle moves freely inside the nucleus, and is emitted after tunneling through the potential barrier between itself and the daughter nucleus. In other words, the $\alpha $-particle, whose energy is $E$, is trapped in a potential well of radius $R$ by the potential barrier

$\displaystyle U(r) = \frac{Z_1\,Z_2\,e^{\,2}}{4\pi\,\epsilon_0\,r}$ (11.133)

for $r>R$. Here, $e$ is the magnitude of the electron charge.

Making use of the WKB approximation (and neglecting the fact that $r$ is a radial, rather than a Cartesian, coordinate), the probability of the $\alpha $-particle tunneling through the barrier is

$\displaystyle \vert T\vert^{\,2} = \exp\left(-\frac{2\sqrt{2\,m}}{\hbar}\int_{r_1}^{r_2}
\sqrt{U(r)-E}\,dr\right),$ (11.134)

where $r_1=R$ and $r_2 = Z_1\,Z_2\,e^{\,2}/(4\pi\,\epsilon_0\,E)$. Here, $m=4\,m_p$ is the $\alpha $-particle mass, and $m_p$ is the proton mass. The previous expression reduces to

$\displaystyle \vert T\vert^{\,2} = \exp\left[-2\sqrt{2}\,\beta \int_{1}^{E_c/E}\left(\frac{1}{y}-\frac{E}{E_c}\right)^{1/2} dy\right],$ (11.135)

where

$\displaystyle \beta = \left(\frac{Z_1\,Z_2\,e^{\,2}\,m\,R}{4\pi\,\epsilon_0\,\hbar^{\,2}}\right)^{1/2} = 0.74\,Z_1^{\,2/3}$ (11.136)

is a dimensionless constant, and

$\displaystyle E_c = \frac{Z_1\,Z_2\,e^{\,2}}{4\pi\,\epsilon_0\,R} = 1.44\,Z_1^{\,2/3}\,\,{\rm MeV}$ (11.137)

is the characteristic energy the $\alpha $-particle would need in order to escape from the nucleus without tunneling. Of course, $E\ll E_c$. It is easily demonstrated that

$\displaystyle \int_1^{1/\epsilon}\left(\frac{1}{y} - \epsilon\right)^{1/2} dy \simeq
\frac{\pi}{2\sqrt{\epsilon}}-2$ (11.138)

when $\epsilon\ll 1$. Hence.

$\displaystyle \vert T\vert^{\,2} \simeq \exp\left[-2\sqrt{2}\,\beta\left(\frac{\pi}{2}\sqrt{\frac{E_c}{E}}-2\right)\right].$ (11.139)

Now, the $\alpha $-particle moves inside the nucleus at the characteristic velocity $v= \sqrt{2\,E/m}$. It follows that the particle bounces backward and forward within the nucleus at the frequency $\nu\simeq v/R$, giving

$\displaystyle \nu\simeq 2\times 10^{28}\,\,{\rm yr}^{-1}$ (11.140)

for a 1 MeV $\alpha $-particle trapped inside a typical heavy nucleus of radius $10^{-14}$ m. Thus, the $\alpha $-particle effectively attempts to tunnel through the potential barrier $\nu$ times a second. If each of these attempts has a probability $\vert T\vert^{\,2}$ of succeeding then the probability of decay per unit time is $\nu\,\vert T\vert^{\,2}$. Hence, if there are $N(t)\gg 1$ intact nuclei at time $t$ then there are only $N+dN$ at time $t+dt$, where

$\displaystyle dN = - N\,\nu\,\vert T\vert^{\,2}\,dt.$ (11.141)

This expression can be integrated to give

$\displaystyle N(t) = N(0)\,\exp\left(-\nu\,\vert T\vert^{\,2}\,t\right).$ (11.142)

The half-life, $\tau$, is defined as the time which must elapse in order for half of the nuclei originally present to decay. It follows from the previous formula that

$\displaystyle \tau = \frac{\ln 2}{\nu\,\vert T\vert^{\,2}}.$ (11.143)

Note that the half-life is independent of $N(0)$.

Finally, making use of the previous results, we obtain

$\displaystyle \log_{10}[\tau ({\rm yr})] = -C_1 - C_2\,Z_1^{\,2/3} + C_3\,\frac{Z_1}{\sqrt{E({\rm MeV})}},$ (11.144)

where

$\displaystyle C_1$ $\displaystyle = 28.5,$ (11.145)
$\displaystyle C_2$ $\displaystyle = 1.83,$ (11.146)
$\displaystyle C_3$ $\displaystyle = 1.73.$ (11.147)

Figure 11.13: The experimentally determined half-life, $\tau _{{\rm ex}}$, of various atomic nuclei that decay via $\alpha $-emission versus the best-fit theoretical half-life $\log_{10}(\tau_{{\rm th}}) = -28.9 - 1.60\,Z_1^{\,2/3} + 1.61\,Z_1/\sqrt{E}$. Both half-lives are measured in years. Here, $Z_1=Z-2$, where $Z$ is the charge-number of the nucleus, and $E$ the characteristic energy of the emitted $\alpha $-particle in MeV. In order of increasing half-life, the points correspond to the following nuclei: Rn 215, Po 214, Po 216, Po 197, Fm 250, Ac 225, U 230, U 232, U 234, Gd 150, U 236, U 238, Pt 190, Gd 152, Nd 144. (Data obtained from International Atomic Energy Agency, Nuclear Data Center.)
\includegraphics[width=0.85\textwidth]{Chapter11/fig11_13.eps}

The half-life, $\tau$, the daughter charge-number, $Z_1=Z-2$, and the $\alpha $-particle energy, $E$, for atomic nuclei that undergo $\alpha $-decay are indeed found to satisfy a relationship of the form (11.144). The best fit to the data (see Figure 11.13) is obtained using

$\displaystyle C_1$ $\displaystyle = 28.9,$ (11.148)
$\displaystyle C_2$ $\displaystyle = 1.60,$ (11.149)
$\displaystyle C_3$ $\displaystyle = 1.61.$ (11.150)

It can be seen that these values are remarkably similar to those calculated previously.